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Y = x2 − 4x − 5 y = x 2 4 x 5 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 4 x − 5 x 2 4 x 5 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = − 4, c = − 5 a = 1, b = 4, c = 5 Consider the vertex form of a parabola Answer y = x² 4x 12 When y = 0 x² 4x 12 = 0 x² 4x 12 = 0 (x 2)(x 6) = 0 x = 2 or x = 6 The xintercepts are 2 and 6 y = (x² 4x) 12 yAnswer Vertex form of quadratic equation is => Y = a(X h)^2 k Let's simplify the given equation Add and subtract coefficient of X^2 on left side Y = 4X^2 8X 4 4 3 => Y = 4(X^2 2X 1) 4 3 => Y = 4(X 1)^2 1 So vertex of this parabola is V = (1,1) Solution What Is The Equation Of The Axis Of Symmetry The Coordinates Of The Vertex Of The Graph Of Each Function For Y X 2 2x 5 Y X 2 4x 1 Y 2x 2 4x 2 Y=x^2-4x-5 vertex